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 Post subject: Re: The Math Problem Thread
PostPosted: Mon Jun 02, 2008 6:01 pm 
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Lieutenant Kung Fu-Waffles
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The distance formula is

d = √(x1 − x2)2 + (y1 − y2)2

It works because of the pythagorean theorem, I'll put up a drawing.

http://imageflock.com/img/1212444083.bmp

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 Post subject: I wonder what happens when I change the subject...
PostPosted: Mon Jun 02, 2008 7:04 pm 
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I told you it was easy.

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 Post subject: Re: The Math Problem Thread
PostPosted: Mon Jun 02, 2008 7:54 pm 
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Yeah.

Image

Find X and C.

(REALLY easy)

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 Post subject: Re: The Math Problem Thread
PostPosted: Tue Jun 03, 2008 6:10 pm 
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X=60 degrees
C=square-root of 29

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 Post subject: Re: The Math Problem Thread
PostPosted: Tue Jun 03, 2008 7:01 pm 
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Correct.

Do the following lengths make a right triangle?

3, 6, 7

67, 89, 92

439052845, 458904587, 578973453

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 Post subject: Re: The Math Problem Thread
PostPosted: Tue Jun 03, 2008 8:19 pm 
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no

no


I'm not gonna do the third due to sheer calculation. And Lazyness.

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 Post subject: Re: The Math Problem Thread
PostPosted: Tue Jun 03, 2008 8:46 pm 
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Correct for the first two, but the last one remains unsolved:

Do the following lengths make a right triangle?

439052845, 458904587, 578973453

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 Post subject: Re: The Math Problem Thread
PostPosted: Sat Mar 06, 2010 1:47 pm 
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Double post and bump, but I feel like the addition of [math] makes it okay.


Find the x and y intercepts, if any.


Find the x and y intercept(s), if any. Find the vertical and horizontal asymptote(s), if any. State the domain and range in interval notation.

X intercept(s): (and , if needed)
Y intercept(s): (and , if needed)
Vertical asymptote(s): (and , if needed)
Horizontal Asymptote(s): (and , if needed)
Domain:
Domain:

EDIT: Phred, the answer to your problem is as such:
Year 5, Month 12: Deposit: 2743.37. Salary: 146.41.
(http://officialgms.com/project/math_problem.php)

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 Post subject: Re: The Math Problem Thread
PostPosted: Sat Mar 06, 2010 4:04 pm 
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wow, that dude's fuckin' broke.
MM wrote:

Find the x and y intercept(s), if any. Find the vertical and horizontal asymptote(s), if any. State the domain and range in interval notation.

f(x)=3x^2/(x+4)(x-4)...
so, asymptotes at x=4 and x=-4.
is interval the whole ()[] thing?
If so:
domain: (-infinity,infinity) Except, y'know, 4 and -4.
range: [0,infinity)
intercept at origin. Unless I"m high, which I am.

Be warned, this is first glance, and I haven't done math in forever. So fuckit. I have a feeling it's wrong.

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 Post subject: Re: The Math Problem Thread
PostPosted: Sat Mar 06, 2010 5:16 pm 
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Asymptotes are correct.
Domain is not correct, write it using the template I had above. Not that hard.

Same for range, but that's not correct anyways. Try graphing it.
Intercepts are at origin, correct.

Given that and
Evaluate:

(dot product. result is a scalar)
(cross product. result is another vector.)

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 Post subject: Re: The Math Problem Thread
PostPosted: Fri Mar 12, 2010 7:12 pm 
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MM wrote:
Asymptotes are correct.
Domain is not correct, write it using the template I had above. Not that hard.

Same for range, but that's not correct anyways. Try graphing it.
Intercepts are at origin, correct.

Given that and
Evaluate:

(dot product. result is a scalar)
(cross product. result is another vector.)


Dot = 4*5+7*9+3*2 = 20+63+6 = |89|
Cross = a2b3-a3b2, a3b1-a1b3, a1b2-a2b1 = <7*2 - 3*9, 3*5 - 4*2, 4*9 - 7*5> = <14 - 27, 14 - 8, 36 - 35> = |<-13, 6, 1>|
Mag = sqrt(a1^2 + a2^2 + a3^2) = sqrt(16 + 49 + 9) = |sqrt(74)|
Normalized = |<4/sqrt74, 7/sqrt74, 3/sqrt74>|

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 Post subject: Re: The Math Problem Thread
PostPosted: Tue Mar 16, 2010 5:28 pm 
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I actually got <-13, 7, 1> for the cross product. And a completely different magnitude. Try those again.

Also, the domain/range?

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 Post subject: Re: The Math Problem Thread
PostPosted: Wed Mar 17, 2010 2:29 pm 
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Weird. I'm sure that magnitude is right. And the cross product, yeah. I multiplied 3 and 5 to make 14. Weird.

Domain:
Range:

Solve: log(1*2*3*4...9*10) without a calculator. You are given that log2 = .301, log3 = .477, log7 = .845.
Hint: Show all steps, i.e. the factoring you do.

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 Post subject: Re: The Math Problem Thread
PostPosted: Wed Mar 17, 2010 10:31 pm 
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log (1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10)
log (2 * 3 * 2 * 2 * 3 * 10 * 7 * 2 * 2 * 2 * 3 * 3 * 10)
log2 + log3 + 2log2 + log3 + log10 + log7 + 3log2 + 2log3 + log10
6log2 + 4log3 + log7 + 2log10
6(.301) + 4(.477) + .845 + 2(1)
1.806 + 1.908 + .845 + 2
|6.559|

------- Merged -------

E - with a calculator, I get log(3 628 800) = 6.55976303 which works.

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